Question

Корень из а+корень из b > корень из а+b, если а>0, b>0

Answer 1

Корень d 
если не понятно могу подробно

Answer 2

Answer:

The given expression is: √a + √b > √(a + b), where a > 0 and b > 0.

To determine if the given inequality is true, we can square both sides of the inequality and simplify the expression.

Taking the square of both sides, we get:

(√a + √b)² > (√(a + b))²

Expanding both sides of the inequality, we have:

a + 2√ab + b > a + b

Simplifying the expression, we can cancel out the common terms:

2√ab > 0

Since a and b are both positive, the square root of their product (√ab) will also be positive. Therefore, the inequality 2√ab > 0 is always true.

Hence, the given inequality √a + √b > √(a + b) is always true when a > 0 and b > 0.