Question

3x^2-25=0 как решитья, я забыл.

Answer 1

$3x^2-25=0$
$( \sqrt{3})^2 x^2-5^2=0$
$( \sqrt{3}x)^2-5^2=0$
$( \sqrt{3}x-5)( \sqrt{3}x+5)=0$
$\sqrt{3}x-5=0,or, \sqrt{3}x+5=0$
$x= \frac{5}{ \sqrt{3} } ,or, x=- \frac{5}{ \sqrt{3} }$

Ответ: $\frac{5}{ \sqrt{3} } ;- \frac{5}{ \sqrt{3} }$

Answer 2

Solving the Equation 3x^2 - 25 = 0

To solve the equation 3x^2 - 25 = 0, we can use the quadratic formula, which states that for an equation in the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

In the case of the equation 3x^2 - 25 = 0, we can identify a = 3, b = 0, and c = -25.

Applying the Quadratic Formula

Using the quadratic formula, the solutions for x can be calculated as follows:

x = (-0 ± √((0)^2 - 4*3*(-25))) / (2*3)

x = ± √(0 + 300) / 6

x = ± √300 / 6

Simplifying the Solutions

Simplifying the square root of 300, we get:

x = ± √(100 * 3) / 6

x = ± 10√3 / 6

So, the solutions for the equation 3x^2 - 25 = 0 are:

x = (10√3) / 6 and x = -(10√3) / 6

Therefore, the solutions for the given equation are x = (10√3) / 6 and x = -(10√3) / 6.