Question

Сколько кг воды нужно выпарить из 0.5т целлюлозной масы, сод. 85% воды, чтобы получить массу с 75% сод. воды? Можете решить табличкой. Пожалуйста

Answer 1

Решение:
В 0,5т массы целлюлозы содержится
0,15*0,5=0,075т. целлюлозы
0,25*(0,5-х) =0,075
х=0,2т=200кг
Ответ: 200кг

Решение. Целюлозы: 0,5*0,15=0,075; x/(x+0,075)=0,75; x=0,75*x+0,075*0,75; x=(0,075*0,75)/0,25=0,225; Испарили: 0,5-(0,225+0,075)=0,2(т).

Answer 2

Calculating Water Evaporation from Cellulose Pulp

To calculate the amount of water that needs to be evaporated from 0.5 tons of cellulose pulp to obtain a mass with 75% water content, we can use a simple table to illustrate the process.

Let's start by breaking down the given information: - Initial mass of cellulose pulp = 0.5 tons - Initial water content in cellulose pulp = 85% - Desired water content in the final mass = 75%

| Stage | Mass of Cellulose Pulp (tons) | Water Content | Actual Water (tons) | Desired Water (tons) | Water to Evaporate (tons) | |-------|-------------------------------|----------------|----------------------|----------------------|--------------------------| | Initial | 0.5 | 85% | 0.5 * 0.85 = 0.425 | 0.5 * 0.75 = 0.375 | 0.425 - 0.375 = 0.05 | | Final | 0.5 | 75% | - | 0.5 * 0.75 = 0.375 | - |

So, to obtain a mass with 75% water content from 0.5 tons of cellulose pulp with 85% water content, 0.05 tons of water needs to be evaporated.

I hope this table helps clarify the process! If you have any further questions or need additional assistance, feel free to ask.