Question

Разложить на множители 1)ху+5у-3х-15 2)х³-2х²+х-2 Срочно ребят Срочно пожалуйста

Answer 1

1).( xy-3x)+(5y-15)=x(y-3)+5(y-3)=(y-3)(x+5); 2). (x^3-2x^2)+(x-2)=x^2(x-2)+(x-2)=(x-2)(x^2+1).

Answer 2

Factoring Expressions

To factor the given expressions, let's take them one by one:

1) ху + 5у - 3х - 15

To factor this expression, we can group the terms:

(ху - 3х) + (5у - 15)

Now, let's factor out the common factors from each group:

х(у - 3) + 5(у - 3)

Notice that we have a common factor of (у - 3) in both terms. We can factor it out:

(у - 3)(х + 5)

Therefore, the factored form of the expression ху + 5у - 3х - 15 is (у - 3)(х + 5).

2) х³ - 2х² + х - 2

To factor this expression, we can look for common factors among the terms. In this case, there are no common factors among all the terms.

However, we can still try to factor it by grouping:

(х³ - 2х²) + (х - 2)

Now, let's factor out the common factors from each group:

х²(х - 2) + 1(х - 2)

Again, we have a common factor of (х - 2) in both terms. We can factor it out:

(х - 2)(х² + 1)

Therefore, the factored form of the expression х³ - 2х² + х - 2 is (х - 2)(х² + 1).

I hope this helps! Let me know if you have any further questions.