Question

При каких значениях а график функций у=ax2 проходит через точку 1) A(2; 2) ; 2) B(2;-2); 3) C(-3; 6); 4) D(-3;-6); 5) E( 1/2;1,5); 6) F(-2/3;4/3)?

Answer 1

Просто каждый раз подставляешь x i y  из сменной под уравнение и считаешь

Answer 2

Finding the Values of 'a' for the Given Points

To find the values of 'a' for the given points A(2, 2), B(2, -2), C(-3, 6), D(-3, -6), E(1/2, 1.5), and F(-2/3, 4/3) through the function y = ax^2, we can use the fact that the function passes through these points.

The general form of the quadratic function is y = ax^2. We can substitute the x and y values of each point into this equation to find the value of 'a' for each point.

1) For point A(2, 2): - Substituting x = 2 and y = 2 into the equation y = ax^2, we get: 2 = 4a a = 0.5 2) For point B(2, -2): - Substituting x = 2 and y = -2 into the equation y = ax^2, we get: -2 = 4a a = -0.5 3) For point C(-3, 6): - Substituting x = -3 and y = 6 into the equation y = ax^2, we get: 6 = 9a a = 2/3 4) For point D(-3, -6): - Substituting x = -3 and y = -6 into the equation y = ax^2, we get: -6 = 9a a = -2/3 5) For point E(1/2, 1.5): - Substituting x = 1/2 and y = 1.5 into the equation y = ax^2, we get: 1.5 = a/4 a = 6 6) For point F(-2/3, 4/3): - Substituting x = -2/3 and y = 4/3 into the equation y = ax^2, we get: 4/3 = 4a/9 a = 3/2

Conclusion

The values of 'a' for the given points A(2, 2), B(2, -2), C(-3, 6), D(-3, -6), E(1/2, 1.5), and F(-2/3, 4/3) through the function y = ax^2 are as follows: - For point A: a = 0.5 - For point B: a = -0.5 - For point C: a = 2/3 - For point D: a = -2/3 - For point E: a = 6 - For point F: a = 3/2