Question

Задачу решите с помощью уравнения! За три дня продали 15 т картофеля. В первый день продали на 1 т меньше, чем во второй, а в третий - две третьи того , что в первый и второй день вместе . сколько тонн картофеля продали в каждый из трех дней?

Answer 1

Немного грязно написано но надеюсь разберетесь держи фотку

Answer 2

Problem Analysis

We are given that 15 tons of potatoes were sold over three days. On the first day, the quantity sold was 1 ton less than the second day, and on the third day, it was two-thirds of the total quantity sold on the first and second days combined. We need to find the quantity of potatoes sold on each of the three days.

Solution

Let's assume the quantity of potatoes sold on the second day is x tons.

According to the problem, the quantity sold on the first day is 1 ton less than the second day, so it is (x - 1) tons.

The quantity sold on the third day is two-thirds of the total quantity sold on the first and second days combined. The total quantity sold on the first and second days is (x + (x - 1)) = (2x - 1) tons. Therefore, the quantity sold on the third day is (2/3) * (2x - 1) tons.

The sum of the quantities sold on all three days is equal to 15 tons. So we can write the equation:

(x - 1) + x + (2/3) * (2x - 1) = 15

Now we can solve this equation to find the value of x, which represents the quantity of potatoes sold on the second day.