Question

Разложите на множители x²y+xy²-2-x-y+2xy. Решите пожалуйста! СРОЧНО!

Answer 1

$x^2y+xy^2+2xy-2-x-y=$
Выносим общий множитель:
$xy(x+y+2)-(x+y+2)=\boxed{(x+y+2)(xy-1)}$

Answer 2

(2х+у)(1-2х+у) вот думаю это правельно

Answer 3

Factoring the Expression

To factor the given expression x²y + xy² - 2 - x - y + 2xy, we can first rearrange the terms to group them appropriately:

x²y + xy² + 2xy - x - y - 2

Now, we can factor by grouping:

(x²y + xy²) + (2xy - x) - (y + 2)

Factoring out common terms from each group:

xy(x + y) + x(2y - 1) - (y + 2)

Now, we can factor out the common factor from the first two terms:

xy(x + y) + x(2y - 1) - 1(y + 2)

Factored Expression

So, the factored form of the given expression x²y + xy² - 2 - x - y + 2xy is:

xy(x + y) + x(2y - 1) - 1(y + 2)

Solution

The expression factored into xy(x + y) + x(2y - 1) - 1(y + 2).