Question

5Х(в квадрате)-2х-39=0 Найдите Дискриминант

Answer 1

D=b^2-4ac=(-2)^2-4*5*(-39)=4+780=784
x1=(-b)+sqrt(D)/2a=2+28/10=3
x2=(-b)-sqrt(D)=2-28/10=-2,6

Answer 2

5х2-2х-39=0
Д=4+780=784=28
х=2-28/10=-2,6
х=2+28/10=3

Answer 3

I can help you with your math problem. The equation you have is $$5x^2-2x-39=0$$ and you want to find the discriminant. The discriminant is the part of the quadratic formula that determines how many real solutions the equation has. It is calculated by $$b^2-4ac$$ where $$a$$, $$b$$, and $$c$$ are the coefficients of the equation. In your case, $$a=5$$, $$b=-2$$, and $$c=-39$$. So the discriminant is $$(-2)^2-4(5)(-39)=796$$. This means that the equation has two real solutions.Ответь+подробно.+5Х(в+квадрате)-2х-39=0+Найдите+Дискриминант