Question

1)arccos1+arcsin02)arccos(-1/2)-arcsinкщрень из 3 на 2

Answer 1

1)arccos1+arcsin0 = 0,5π + 0 = 0,5π

2)arccos(-1/2)- arcsin(0,5√3) = 2π/3 - π/3 = π/3

Answer 2

1) arccos(1) + arcsin(0)

arccos(1) is equal to 0 because the cosine of 0 degrees is 1. arcsin(0) is also equal to 0 because the sine of 0 degrees is 0.

So, arccos(1) + arcsin(0) = 0 + 0 = 0

2) arccos(-1/2) - arcsin(3/2)

To find arccos(-1/2), we need to find the angle whose cosine is -1/2. This occurs in the second quadrant, so we have arccos(-1/2) = 2π/3.

To find arcsin(3/2), we need to find the angle whose sine is 3/2. However, the sine function only takes values between -1 and 1, so there is no angle whose sine is 3/2. Therefore, arcsin(3/2) is not defined.

So, arccos(-1/2) - arcsin(3/2) = 2π/3 - undefined = undefined