Question

Прямая АС проходит через начало координат и точку C(-1; 4). Графиком какой функции является эта прямая?​

Answer 1

Ответ:

у=-4х

Объяснение:

Т.к. прямая проходит через начало координат, то прямая задано уравнением у=кх

Дана точка, где х= -1, у = 4.

Поставляем и находим к
4=к*(-1)

к= (-4)

Получим уравнение у=-4х

Answer 2

The equation of the line passing through the origin and point C(-1, 4)

To determine the equation of the line passing through the origin (0, 0) and point C(-1, 4), we can use the slope-intercept form of a linear equation, which is given by:

y = mx + b

where: - m is the slope of the line, and - b is the y-intercept of the line.

To find the slope (m), we can use the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) represents the coordinates of the origin (0, 0), and (x2, y2) represents the coordinates of point C(-1, 4).

Substituting the values into the formula, we get:

m = (4 - 0) / (-1 - 0) = 4 / -1 = -4

So, the slope of the line is -4.

Now, we can substitute the slope (m) and the coordinates of the origin (0, 0) into the slope-intercept form to find the y-intercept (b).

0 = -4(0) + b

Simplifying the equation, we get:

0 = b

Therefore, the y-intercept (b) is 0.

Putting it all together, the equation of the line passing through the origin and point C(-1, 4) is:

y = -4x

This means that the graph of this line is a straight line with a slope of -4 and passing through the origin.