Question

Девятикласник придбав 6 книжок з математики, інформатики фізики. Скільки книжок було купленно з кожного предмета якщо з математики книжок купили більше ніж з інформатики, а з фізики- менше ніж з інформаики?

Answer 1

Математика-больше чем Информатика, больше чем физика

Физика- меньше чем Информатика, меньше чем математика

Информатика-

Всего- 6

Математика-3книги>2>1

Физика-1 книга<2<3

Информатика-2 книги

Answer 2

Solution:

To solve this problem, we can use a system of equations to represent the given information and then solve for the number of books purchased for each subject.

Let's denote: - The number of math books as m - The number of computer science books as c - The number of physics books as p

We are given the following information: 1. The 9th grader purchased a total of 6 books: m + c + p = 6 2. More math books were purchased than computer science books: m > c 3. Fewer physics books were purchased than computer science books: p < c

We can use these equations to solve for the values of m, c, and p.

Solution Steps:

1. Start with the equation representing the total number of books purchased: m + c + p = 6 2. Use the information that more math books were purchased than computer science books: m > c 3. Use the information that fewer physics books were purchased than computer science books: p < c

Let's solve for the values of m, c, and p using these equations.

Solution:

Given: - Total number of books purchased: m + c + p = 6 - More math books were purchased than computer science books: m > c - Fewer physics books were purchased than computer science books: p < c

By solving these equations, we can find the values of m, c, and p.