Question

25-[2+5y-3(y+2)]=3(2y-5)-[5(y-1)-3y+3]

Answer 1

25-(2+5у-3(у+2))=3(2у-5)-(5(у-1)-3у+3)
25-(2+5у-3у-6)=6у-15-(5у-5-3у+3)
25-(2у-4)=6у-15-(2у-2)
25-2у+4=6у-15-2у+2
-6у=-15+2-25-4
-6у=-42
у=7

Answer 2

To solve the equation, let's start by simplifying and expanding the expressions on both sides:

25 - [2 + 5y - 3(y + 2)] = 3(2y - 5) - [5(y - 1) - 3y + 3]

First, distribute the -3 inside the square brackets on the left side and the 5 inside the square brackets on the right side:

25 - [2 + 5y - 3y - 6] = 3(2y - 5) - [5y - 5 - 3y + 3]

Now, simplify the expressions inside the square brackets:

25 - (2 + 5y - 3y + 6) = 3(2y - 5) - (5y - 5 - 3y + 3)

Combine like terms:

25 - (2y + 4) = 3(2y - 5) - (2y - 2)

Now, distribute the 3 on the right side:

25 - 2y - 4 = 6y - 15 - 2y + 2

Combine like terms on both sides:

(25 - 4) - 2y = (6y - 2y) - (15 + 2)

21 - 2y = 4y - 13

Now, isolate the variable terms on one side:

21 + 13 = 4y + 2y

34 = 6y

Finally, solve for y by dividing both sides by 6:

y = 34 / 6

y = 17/3

So, the solution to the equation is:

y = 17/3