Question

Log1/6 (7x-9)= log1/6

Answer 1

Log1/6 (4-2x)=log1/6 364-2x=36-2x=32x=-16

Answer 2

It seems like you have an equation involving logarithms with a base of 1/6. The equation you've written is:

log1/6 (7x - 9) = log1/6

To solve this equation, you can use the properties of logarithms. Since both sides of the equation have the same base (1/6), and the logarithms are equal, the arguments inside the logarithms must also be equal:

7x - 9 =

Now, solve for x:

7x - 9 =

Add 9 to both sides of the equation:

7x = 9

Finally, divide both sides by 7 to isolate x:

x = 9/7

So, the solution to the equation is:

x = 9/7