Question

F(x) = х2 - cos 2x + tg2х​

Answer 1

Ответ:f(x)=x*2-cos(2x)+tg*2x====f'(x)=2+2sin(2x)+2gt

Объяснение:

Answer 2

The function you've given is $F(x) = x^2 - \cos(2x) + \tan^2(x)$.

Here's how you can break down and analyze this function:

1. $x^2$ - This term represents a simple quadratic function, where $x$ is squared.

2. $\cos(2x)$ - This term involves the cosine of $2x$, which is a periodic function that oscillates between -1 and 1 as $x$ varies.

3. $\tan^2(x)$ - This term is the square of the tangent function, $\tan(x)$, which is unbounded and can take on a wide range of values.

To understand the behavior of the function $F(x)$, you need to consider how these three components interact:

• The $x^2$ term is always non-negative and increases as $x$ gets farther from zero in either direction.

• The $\cos(2x)$ term oscillates between -1 and 1. This term can have both positive and negative values.

• The $\tan^2(x)$ term is always non-negative and can be very large when $\tan(x)$ is large.

So, the overall behavior of $F(x)$ will depend on the balance between these three components. The quadratic term $x^2$ will tend to make the function grow as you move away from zero, while the $\cos(2x)$ term and the $\tan^2(x)$ term will introduce oscillations and can lead to sharp peaks and valleys.

Without a specific range or constraints on the values of $x$, it's challenging to provide a precise analysis of the function's behavior. To fully understand $F(x)$ and its behavior, you might need to consider specific intervals or values of $x$ and analyze it numerically or graphically.