Question

(х-2)(х+1). оаоалаоаоаоа​

Answer 1

Ответ:

$x^{2} -x-1$

Объяснение:

Разкрываем скобки

$x^{2} +x-2x-2$
$x^{2} -x-1$

Answer 2

It looks like you've provided the expression "(х-2)(х+1)" which appears to be a quadratic equation or polynomial. If you'd like to simplify or solve this equation, I can help with that.

To simplify the expression, you can use the distributive property to expand it:

(х-2)(х+1) = х(х+1) - 2(х+1)

Now, you can multiply each term:

х(х+1) = х^2 + х -2(х+1) = -2х - 2

So, the simplified expression is:

х^2 + х - 2х - 2

Now, you can combine like terms:

х^2 - х - 2

If you want to solve this quadratic equation for х, you can set it equal to zero and use the quadratic formula or factoring:

х^2 - х - 2 = 0

You can factor this equation as follows:

(х - 2)(х + 1) = 0

Now, you can set each factor equal to zero:

х - 2 = 0 or х + 1 = 0

Solving for х in each equation:

For х - 2 = 0: х = 2

For х + 1 = 0: х = -1

So, the solutions for the equation х^2 - х - 2 = 0 are х = 2 and х = -1.