Question

(3x-4)(x + 5) - x(x + 5) = 0​

Answer 1

Ответ:

(3x-4)х(x+5)-xx (x+5)=0

(x+5)х(3x-4-x)=0

(x+5)х(2х-4)=0

x+5=0

2х-4=0

x=-5

x=2

Уравнение имеет 2 решения

Решение:

x1=-5, X2=2

Answer 2

3х²+15х-4х-20-х²-5х=0

2х²+6х-20=0

х²+3х-10=0

х1=-5, х2=2

Answer 3

To solve the equation (3x-4)(x + 5) - x(x + 5) = 0, you can follow these steps:

1. Expand both sides of the equation:

(3x - 4)(x + 5) - x(x + 5) = 0

Expanding the expressions on both sides:

(3x^2 + 15x - 4x - 20) - (x^2 + 5x) = 0

Now, simplify the equation:

3x^2 + 11x - 20 - x^2 - 5x = 0

2. Combine like terms:

(3x^2 - x^2) + (11x - 5x) - 20 = 0

This simplifies further to:

2x^2 + 6x - 20 = 0

3. Divide the entire equation by the greatest common divisor, which in this case is 2:

x^2 + 3x - 10 = 0

4. Now, you have a quadratic equation. To solve it, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 1, b = 3, and c = -10. Plug these values into the quadratic formula:

x = (-3 ± √(3² - 4(1)(-10))) / (2(1))

x = (-3 ± √(9 + 40)) / 2

x = (-3 ± √49) / 2

x = (-3 ± 7) / 2

Now, find the two possible values of x:

x1 = (-3 + 7) / 2 = 4 / 2 = 2 x2 = (-3 - 7) / 2 = -10 / 2 = -5

So, the solutions to the equation are x = 2 and x = -5.