Question

(3/4)^-1*(√6)^2-(1/√5)-2

Answer 1

$(\frac{3}{4})^{-1} *\sqrt{6} ^{2} - \frac{1}{\sqrt{5} }-2 = \frac{4}{3} * 6 - \frac{\sqrt{5} }{5}-2 = 4 *2 - \frac{\sqrt{5} }{5} -2 = 8 - \frac{\sqrt{5} }{5}-2 = 6-\frac{\sqrt{5} }{5}$

Answer 2

Let's break down the expression step by step:

1. $(3/4)^{-1}$ means taking the reciprocal of $\frac{3}{4}$, which is $\frac{1}{3/4}$, or $\frac{4}{3}$.

2. $(\sqrt{6})^2$ means squaring the square root of 6, which is simply 6.

3. $\frac{1}{\sqrt{5}}$ can be written as $\sqrt{5}^{-1}$, which is the reciprocal of the square root of 5.

Now, let's plug these values back into the original expression:

$\frac{4}{3} \times 6 - \sqrt{5}^{-1} - 2$

Now, let's simplify further:

$\frac{4}{3} \times 6 = \frac{24}{3} = 8$

$\sqrt{5}^{-1} = \frac{1}{\sqrt{5}} = \frac{\sqrt{5}}{5}$

Now, the expression becomes:

$8 - \frac{\sqrt{5}}{5} - 2$

Combine the constants:

$8 - 2 - \frac{\sqrt{5}}{5}$

$6 - \frac{\sqrt{5}}{5}$