Question

X^2-4x-5 ------------- = 0 x^2+1+2x

Answer 1

X^2-4x-5
------------- = 0 x не равно - 1
x^2+1+2x
Умножаем обе части на знаменатель, и получаем:
x^2-4x-5=0
D=в^2-4ac=16+20=36
X1=-v+/D:2a=4+6:2=5
X2=-v1/D:2a=4-6:2=-1
Ответ: x=5

Answer 2

To solve the quadratic equation $\frac{x^2 - 4x - 5}{x^2 + 1 + 2x} = 0$, we can start by factoring the numerator and denominator separately.

The given equation is:

$\frac{x^2 - 4x - 5}{x^2 + 1 + 2x} = 0$

Factor the numerator:

$(x - 5)(x + 1)$

Factor the denominator:

$(x + 1)(x + 1)$

Now the equation becomes:

$\frac{(x - 5)(x + 1)}{(x + 1)(x + 1)} = 0$

Cancel out the common factor of $x + 1$ from the numerator and denominator:

$\frac{x - 5}{x + 1} = 0$

Now, set the numerator equal to zero:

$x - 5 = 0$

Add 5 to both sides:

$x = 5$

So, the solution to the given equation is $x = 5$.