Question

(3+x) (x-3)-(3-x) ^2​

Answer 1

$(3+x)(x-3)-(3-x)^2=\underbrace {(x-3)(x+3)}_{x^2-3^2}-(9-6x+x^2)=\\\\=x^2-9-9+6x-x^2=6x-18=6\, (x-3)$

Answer 2

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Готово!!Удачи:)))

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Answer 3

Let's simplify the expression step by step:

1. Expand the first term, (3+x)(x-3): (3+x)(x-3) = 3(x) - 3(3) + x(x) - x(3) = 3x - 9 + x^2 - 3x

2. Expand the second term, (3-x)^2: (3-x)^2 = (3-x)(3-x) = 9 - 3x - 3x + x^2 = 9 - 6x + x^2

Now, subtract the second term from the first term:

(3+x)(x-3) - (3-x)^2 = (3x - 9 + x^2 - 3x) - (9 - 6x + x^2)

Now, let's simplify further:

3x - 9 + x^2 - 3x - 9 + 6x - x^2

Now, combine like terms:

(3x - 3x) + (x^2 - x^2) + (-9 - 9 + 6x)

The x^2 and x^2 terms cancel out, and you're left with:

6x - 18

So, the simplified expression is:

6x - 18