Question

Log1/5log3log2(1-x)=0​

Answer 1

Ответ:

$-7$

Объяснение:

$log_{\frac{1}{5}}log_3log_2(1-x)=0\\\\1-x>0\\x$

Answer 2

To solve the equation $\log_{\frac{1}{5}}\left(3\log_2(1-x)\right) = 0$, we'll use the properties of logarithms:

1. $\log_a(b) = c$ is equivalent to $a^c = b$.

2. $\log_a(a) = 1$.

Let's proceed with the solution:

Given: $\log_{\frac{1}{5}}\left(3\log_2(1-x)\right) = 0$.

Using property 1, we have:

$\frac{1}{5}^0 = 3\log_2(1-x)$

$1 = 3\log_2(1-x)$

Dividing both sides by 3:

$\log_2(1-x) = \frac{1}{3}$

Using property 2:

$2^{\frac{1}{3}} = 1 - x$

Solving for $x$:

$x = 1 - 2^{\frac{1}{3}}$

This is the solution to the equation $\log_{\frac{1}{5}}\left(3\log_2(1-x)\right) = 0$.