Question

(x^2-3x+1)(x^2-3x+3)=3

Answer 1

Ответ: х = 0; х = 3

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Answer 2

To solve the equation $(x^2 - 3x + 1)(x^2 - 3x + 3) = 3$, you can follow these steps:

1. Expand the left side of the equation: $(x^2 - 3x + 1)(x^2 - 3x + 3) = x^4 - 3x^3 + x^2 - 3x^3 + 9x^2 - 3x + x^2 - 3x + 3$ $= x^4 - 6x^3 + 12x^2 - 6x + 3$

2. Set the expression equal to 3: $x^4 - 6x^3 + 12x^2 - 6x + 3 = 3$

3. Subtract 3 from both sides to get the equation in standard form: $x^4 - 6x^3 + 12x^2 - 6x = 0$

Now, you have a quartic equation. Unfortunately, quartic equations do not have a general formula for solutions like quadratic equations do. You may need to use numerical methods or factorization techniques to find the roots. Keep in mind that finding the exact roots might be complex, and in some cases, an approximate solution may be more practical.