Question

3х ^2– 12х = 0 2х^2 + 6х = 0 1,8х^2 = 0 х^2 + 9 = 0 (х + 1)(х – 2) = 0 х ^2– 16 = 0 х^2 = 3х 3х^2 + 7 = 12х + 7 х ^2– 4х + 3 = 0 7х^2 – 4 = 0 3х^2 – х + 2 = 0 Х^2 + 6 = 5х

Answer 1

Ответ:

Объяснение:

1) 0;4

2) 0;-6

3) 0

4) нет решений

5) -1; 2

6) 4; -4

7)0; 3

8) 0; 4

9) 3; 1

10)+- корень из 4/7

11) нет решений

12) 3;2

Answer 2

It looks like you've written down several equations. I'll go through each of them and solve for the variable x:

1. 3x^2 - 12x = 0 Factor out 3x: 3x(x - 4) = 0

   So, x = 0 or x = 4.

2. 2x^2 + 6x = 0 Factor out 2x: 2x(x + 3) = 0

   So, x = 0 or x = -3.

3. 1.8x^2 = 0 Divide both sides by 1.8: x^2 = 0

   So, x = 0.

4. x^2 + 9 = 0 This equation has no real solutions because you cannot take the square root of a negative number and get a real result.

5. (x + 1)(x - 2) = 0 Use the zero-product property: x + 1 = 0 or x - 2 = 0

   So, x = -1 or x = 2.

6. x^2 - 16 = 0 Factor as the difference of squares: (x + 4)(x - 4) = 0

   So, x = 4 or x = -4.

7. x^2 = 3x Move all terms to one side: x^2 - 3x = 0

   Factor out x: x(x - 3) = 0

   So, x = 0 or x = 3.

8. 3x^2 + 7 = 12x + 7 Subtract 12x and 7 from both sides: 3x^2 - 12x = 0

   Factor out 3x: 3x(x - 4) = 0

   So, x = 0 or x = 4.

9. x^2 - 4x + 3 = 0 Factor the quadratic equation: (x - 3)(x - 1) = 0

   So, x = 3 or x = 1.

10. 7x^2 - 4 = 0 Add 4 to both sides: 7x^2 = 4

    Divide by 7: x^2 = 4/7

    Take the square root: x = ±√(4/7)

11. 3x^2 - x + 2 = 0 This quadratic equation does not factor easily. You can use the quadratic formula to solve for x: x = (-b ± √(b^2 - 4ac)) / (2a) where a = 3, b = -1, and c = 2.

    x = (-(-1) ± √((-1)^2 - 4(3)(2))) / (2(3)) x = (1 ± √(1 - 24)) / 6

    Since the discriminant (1 - 24) is negative, there are no real solutions.

12. x^2 + 6 = 5x Move all terms to one side: x^2 - 5x + 6 = 0

    Factor the quadratic equation: (x - 3)(x - 2) = 0

    So, x = 3 or x = 2.

I've solved each of the equations for x as shown above.