Question

Sin(a + пи) + tg(a – пи)​

Answer 1

Відповідь:

- sin(a) + tg(a) = -sin(a) + sin(a)/cos(a) = -cos(a)*sin(a)+ sin(a)/ cos(a)

Answer 2

The expression you provided involves trigonometric functions. Let's break it down step by step:

1. sin(a + π): The sine function evaluates the sine of an angle in radians. Adding π (pi) to an angle simply shifts the angle by half of a full circle (180 degrees). So, sin(a + π) is equal to -sin(a) because the sine function is an odd function, and it changes sign when the angle is shifted by π.

2. tan(a - π): The tangent function evaluates the tangent of an angle in radians. Subtracting π from an angle also shifts the angle by half of a full circle, which is equivalent to a 180-degree rotation. Therefore, tan(a - π) is equal to tan(a) because the tangent function has a period of π (180 degrees), and subtracting π from an angle does not change its tangent value.

So, the expression simplifies to: -sin(a) + tan(a)

These trigonometric functions are now in their simplified form.