Question

6^х -7^х=0решите уравнение

Answer 1

$6^x=7^x\\\\ \frac{6}{7}^x=1\\\\ x=log_{\frac{6}{7}}1\\\\ x=0$

Answer 2

I can help you solve the equation. The equation is 6^x - 7^x = 0. To solve it, we need to use the logarithm function. Here are the steps:

1. Divide both sides by 6^x to get 1 - (7/6)^x = 0. 2. Add (7/6)^x to both sides to get 1 = (7/6)^x. 3. Take the natural logarithm of both sides to get ln(1) = ln((7/6)^x). 4. Use the property of logarithm that ln(a^b) = b*ln(a) to get ln(1) = x*ln(7/6). 5. Divide both sides by ln(7/6) to get x = ln(1) / ln(7/6). 6. Simplify the expression to get x = 0 / ln(7/6) = 0.

Therefore, the solution is x = 0. You can check this by plugging it back into the original equation and see that it is true. I hope this helps. If you need more help, you can ask me another question or visit [this website](https://ru.symbolab.com/solver/equation-calculator) for more examples and explanations.