Question

10(а+3)=-1-6в 6(в+3)=8-3а

Answer 1

Объяснение:

Фото с решением прикрепил

Answer 2

To solve this system of equations:

1. Expand the expressions on both sides:

   For the first equation: 10(a+3) = -1 - 6в 10a + 30 = -1 - 6в

   For the second equation: 6(в+3) = 8 - 3a 6в + 18 = 8 - 3a

2. Now, let's isolate a or в in one of the equations. We'll choose the first equation and isolate 'a':

   10a + 30 = -1 - 6в 10a = -1 - 6в - 30 10a = -31 - 6в

3. Divide both sides of the equation by 10 to solve for 'a':

   a = (-31 - 6в) / 10

4. Substitute the expression for 'a' into the second equation:

   6в + 18 = 8 - 3a 6в + 18 = 8 - 3[(-31 - 6в) / 10]

5. Now, solve for 'в'. Start by distributing the -3:

   6в + 18 = 8 + 3(31 + 6в) / 10

6. Isolate 'в' terms on one side and constants on the other side:

   6в - 3(31 + 6в) / 10 = 8 - 18

7. Simplify:

   6в - (93 + 18в) / 10 = -10

8. Multiply both sides of the equation by 10 to eliminate the fraction:

   60в - 93 - 18в = -10 * 10

9. Combine 'в' terms on the left side:

   60в - 18в - 93 = -100

10. Combine like terms:

42в - 93 = -100

11. Add 93 to both sides:

42в = -100 + 93

12. Simplify:

42в = -7

13. Finally, divide by 42 to solve for 'в':

в = -7 / 42

Now, you have the values of 'a' and 'в'. 'a' is given by: a = (-31 - 6в) / 10

And 'в' is given by: в = -7 / 42

You can simplify в further if needed:

в = -1/6