Question

(1-x^(2))^(2)+3,7(1-x^(2))+2,1=0 пжппжпжпжппжжппжжпжпжппжпжжпжпжпжпж

Answer 1

Ответ:

Объяснение:

(1-x²)²+3.7(1-x²)+2.1 = 0

1-x² = y

y²+3.7y+2.1 = 0

D = 3.7²-4*2.1 = 2.3²

y₁₋₂ = (-3.7±2.3)/2

y₁ = -3,  y₂ = - 0.7

1-x² = -3

x²= 4

x₁ = -2,  x₂ = 2

1-x² = -0,7

x² = 1.7

x₃= -√1.7

x₄ =$\sqrt{1.7$

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Answer 2

It looks like you've written an equation, but it seems to have some unusual characters and formatting. I'll do my best to interpret it and help you solve it.

The equation appears to be:

(1 - x^2)^2 + 3.7(1 - x^2) + 2.1 = 0

To solve this equation, you can follow these steps:

1. Start by simplifying the equation:

(1 - x^2)^2 + 3.7(1 - x^2) + 2.1 = 0

2. Let's make a substitution to simplify the equation further. Let y = 1 - x^2:

y^2 + 3.7y + 2.1 = 0

3. Now, we have a quadratic equation in terms of y. To solve this quadratic equation, you can use the quadratic formula:

y = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 1, b = 3.7, and c = 2.1.

y = (-3.7 ± √(3.7² - 4(1)(2.1))) / (2(1))

4. Calculate the discriminant (the value inside the square root):

Discriminant = 3.7² - 4(1)(2.1)

Discriminant ≈ 13.69 - 8.4

Discriminant ≈ 5.29

5. Now, use the quadratic formula to find the values of y:

y₁ = (-3.7 + √5.29) / 2 y₂ = (-3.7 - √5.29) / 2

6. Calculate y₁ and y₂:

y₁ ≈ (-3.7 + √5.29) / 2 ≈ -0.386 y₂ ≈ (-3.7 - √5.29) / 2 ≈ -2.314

7. Remember that we made the substitution y = 1 - x^2. So, we need to solve for x:

For y₁: 1 - x^2 ≈ -0.386

x^2 ≈ 1 + 0.386 x^2 ≈ 1.386

x ≈ ±√1.386

For y₂: 1 - x^2 ≈ -2.314

x^2 ≈ 1 + 2.314 x^2 ≈ 3.314

x ≈ ±√3.314

So, the solutions for x are approximately:

x₁ ≈ √1.386, x₁ ≈ -√1.386 x₂ ≈ √3.314, x₂ ≈ -√3.314

These are the approximate solutions to the equation.