Question

1)3/8+4/5 2)8x+12=4x 3)-15×(-4)+10 4) 16x-4=20x 5)(-6x)²

Answer 1

Ответ:

1) $\frac{47}{40}$

2) $x= -3$

3) $70$

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Объяснение:

1) $\frac{3}{8} +\frac{4}{5}$

$\frac{15+32}{40}$

$\frac{47}{40}$

2) $8x+12=4x$

$8x-4x=-12$

$4x=-12$

$x= -3$

3) $-15(-4)+10 = 60+10=70$

4) $16x-4=20x$

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Answer 2

Let's solve each of these problems step by step:

1. $\frac{3}{8} + \frac{4}{5}$ To add these fractions, you need to find a common denominator, which in this case is 40. Then, you can add the fractions:

$\frac{3}{8}$ becomes $\frac{15}{40}$ (by multiplying both the numerator and denominator by 5). $\frac{4}{5}$ becomes $\frac{32}{40}$ (by multiplying both the numerator and denominator by 8).

Now you can add them:

$\frac{15}{40} + \frac{32}{40} = \frac{15 + 32}{40} = \frac{47}{40}$

So, $\frac{3}{8} + \frac{4}{5} = \frac{47}{40}$.

2. $8x + 12 = 4x$ To solve for $x$, you need to isolate it on one side of the equation. Start by subtracting $4x$ from both sides:

$8x + 12 - 4x = 4x - 4x$ $4x + 12 = 0$

Now, subtract 12 from both sides:

$4x + 12 - 12 = 0 - 12$ $4x = -12$

Finally, divide both sides by 4 to solve for $x$:

$\frac{4x}{4} = \frac{-12}{4}$ $x = -3$

So, the solution to the equation is $x = -3$.

3. $-15 \times (-4) + 10$ To solve this expression, simply perform the multiplication and addition:

$-15 \times (-4) + 10 = 60 + 10 = 70$

So, $-15 \times (-4) + 10 = 70$.

4. $16x - 4 = 20x$ To solve for $x$, start by subtracting $16x$ from both sides of the equation:

$16x - 4 - 16x = 20x - 16x$ $-4 = 4x$

Now, divide both sides by 4 to solve for $x$:

$\frac{-4}{4} = \frac{4x}{4}$ $-1 = x$

So, the solution to the equation is $x = -1$.

5. $(-6x)^2$ To square a value, you simply multiply it by itself:

$(-6x)^2 = (-6x) \times (-6x) = 36x^2$

So, $(-6x)^2 = 36x^2$.