Question

Первая труба пропускает на 1 л воды в минуту меньше чем вторая. Сколько литров воды в минуту пропускает вторая труба, если резервуар объёмом 110 л она заполняет на 1 мин быстрее чем первая ?

Answer 1

110/x-110/(х+1)=1
х^2+x-110=0
x=10

Вторая труба пропускает 11л/мин

Answer 2

Problem Analysis

We are given that the first pipe allows 1 liter of water per minute less than the second pipe. We also know that the second pipe fills a reservoir with a volume of 110 liters in 1 minute faster than the first pipe. We need to determine the flow rate of the second pipe.

Solution

Let's assume that the flow rate of the second pipe is x liters per minute. According to the given information, the flow rate of the first pipe is x - 1 liters per minute.

We can set up the following equation based on the information given: 110 / (x - 1) = 110 / x + 1

To solve this equation, we can cross-multiply: 110x + 110 = 110x - 110 220 = 110 x = 2

Therefore, the second pipe has a flow rate of 2 liters per minute.

Answer

The second pipe allows 2 liters of water per minute.