Question

(y+2)( y+3) -y( y-1)

Answer 1

Объяснение:

$y ^{2} + 3y + 2y + 6 - y^{2} + y \\ 6y + 6 \\ 6(y + 1)$

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Answer 2

To simplify the expression $(y+2)(y+3) - y(y-1)$, you can follow these steps:

1. Distribute the terms within each parenthesis:

   $(y+2)(y+3) = y(y+3) + 2(y+3)$

2. Now, distribute the $y$ inside the second parenthesis:

   $y(y+3) = y^2 + 3y$

3. Distribute the 2 inside the second parenthesis:

   $2(y+3) = 2y + 6$

4. So, now your expression becomes:

   $y^2 + 3y + 2y + 6 - y(y-1)$

5. Distribute the $-y$ inside the second parenthesis:

   $-y(y-1) = -y^2 + y$

6. Now, your expression is:

   $y^2 + 3y + 2y + 6 - (-y^2 + y)$

7. Simplify further by combining like terms:

   $y^2 + 3y + 2y + 6 + y^2 - y$

8. Combine the $y^2$ terms, the $y$ terms, and the constants:

   $2y^2 + 4y + 6 - y$

9. Finally, simplify further by combining the $4y$ and $-y$:

   $2y^2 + 3y + 6$

So, the simplified expression is $2y^2 + 3y + 6$.