Question

(2x + 3y = 7(x - 3y = 11?​

Answer 1

Ответ:

(6; - $\frac{5}{3}$)

Объяснение:

Сложим оба уравнения:

2х+х+3y-3y=7+11

3х=18

х=6

6-3y=11

-3y=11-6

-3y=5

y= - $\frac{5}{3}$

Answer 2

To solve the system of equations:

1. 2x + 3y = 7
2. x - 3y = 11

You can use either the substitution method or the elimination method. I'll demonstrate the elimination method here:

First, let's multiply the second equation (2) by 2 to make it easier to eliminate one of the variables:

2(x - 3y) = 2(11)

This simplifies to:

2x - 6y = 22

Now, you have the following system of equations:

1. 2x + 3y = 7
2. 2x - 6y = 22

Next, you can subtract equation (2) from equation (1) to eliminate the x variable:

(2x + 3y) - (2x - 6y) = 7 - 22

Now, simplify:

2x + 3y - 2x + 6y = -15

Combine like terms:

9y = -15

Now, divide both sides by 9 to solve for y:

y = -15 / 9 y = -5/3

Now that you have the value of y, you can substitute it back into either equation (1) or (2) to find the value of x. I'll use equation (1):

2x + 3(-5/3) = 7

Simplify:

2x - 5 = 7

Add 5 to both sides:

2x = 7 + 5 2x = 12

Now, divide by 2:

x = 12 / 2 x = 6

So, the solution to the system of equations is:

x = 6 y = -5/3