Question

Y²(y+2)-(y+2)(y²-y+3)=0

Answer 1

У=1
——
у(2 степень) +2у +3=0

Answer 2

To solve the equation $y^2(y+2) - (y+2)(y^2-y+3) = 0$, you can follow these steps:

Step 1: Factor out the common factor of $y+2$: $y^2(y+2) - (y+2)(y^2-y+3) = (y+2) \left( y^2 - (y^2 - y + 3) \right)$

Step 2: Simplify the expression inside the parentheses: $y^2 - (y^2 - y + 3) = y^2 - y^2 + y - 3 = y - 3$

Now, your equation becomes: $(y+2)(y - 3) = 0$

Step 3: Set each factor equal to zero and solve for $y$:

Factor 1: $y + 2 = 0$ Subtract 2 from both sides: $y = -2$

Factor 2: $y - 3 = 0$ Add 3 to both sides: $y = 3$

So, the solutions to the equation are $y = -2$ and $y = 3$.