Question

X^2-6=4x-25-2x^2-18x=0​

Answer 1

Ответ:

см.фото....................

Answer 2

To solve the given quadratic equation, we need to first simplify and combine like terms. The equation you provided is actually two separate equations. Let's rewrite them separately and then solve each one:

1. x^2 - 6 = 4x - 25

2. -2x^2 - 18x = 0

Let's start with the first equation:

1. x^2 - 6 = 4x - 25

First, move all the terms to one side of the equation to set it equal to zero:

x^2 - 4x + 19 = 0

Now, let's attempt to solve this quadratic equation using the quadratic formula:

The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / (2a)

In our equation, a = 1, b = -4, and c = 19. Plug these values into the formula:

x = (-(-4) ± √((-4)² - 4(1)(19))) / (2(1))

x = (4 ± √(16 - 76)) / 2

x = (4 ± √(-60)) / 2

Since the discriminant (the value inside the square root) is negative, the solutions will be complex numbers:

x = (4 ± √(60)i) / 2

Now, let's solve the second equation:

2. -2x^2 - 18x = 0

Factor out -2x from both terms on the left side:

-2x(x + 9) = 0

Now, set each factor equal to zero:

1. -2x = 0 Divide both sides by -2: x = 0

2. x + 9 = 0 Subtract 9 from both sides: x = -9

So, the solutions to the second equation are x = 0 and x = -9.

To summarize, the solutions to the given system of equations are:

For the first equation: x = (4 ± √(60)i) / 2 (complex numbers) For the second equation: x = 0 and x = -9