Question

(6x-4)(x-4)=7(x²-4x-12) ​

Answer 1

Объяснение:

$(6x - 4)(x - 4) = 7( {x}^{2} - 4x - 12)$

$6 {x}^{2} - 24x - 4x + 16 = 7 {x}^{2} - 28x - 84$

$6 {x}^{2} - 28x + 16 = 7 {x}^{2} - 28x - 84$

$6 {x}^{2} + 16 = 7 {x}^{2} - 84$

$6 {x}^{2} - 7 {x}^{2} = - 84 - 16$

$- {x}^{2} = - 100$

$x = 10$

$x = - 10$

Answer 2

Решение на фотографии!

Answer 3

To solve the equation (6x-4)(x-4) = 7(x²-4x-12), follow these steps:

1. First, expand both sides of the equation:

   (6x-4)(x-4) = 7(x²-4x-12)

   (6x^2 - 24x - 4x + 16) = 7x² - 28x - 84

2. Simplify both sides of the equation:

   6x^2 - 28x + 16 = 7x² - 28x - 84

3. To make the equation easier to work with, move all terms to one side:

   6x^2 - 7x² - 28x + 28x + 16 + 84 = 0

4. Combine like terms:

   -x² + 100 = 0

5. Now, isolate the x² term:

   -x² = -100

6. Divide both sides by -1 to isolate x²:

   x² = 100

7. Finally, take the square root of both sides to solve for x:

   x = ±√100

   x = ±10

So, the solutions to the equation (6x-4)(x-4) = 7(x²-4x-12) are x = 10 and x = -10.