Question

(2x-1)+(x+2)(2x-1)=0

Answer 1

Объяснение:

(2x-1)+(x+2)(2x-1)=0

(2x-1)*(1+x+2)=0

2x-1=0 -> x1= 1/2

x+3=0 -> x2=-3

Answer 2

$x = 0.5$

$x = - 3$

В цьому рівнянні дві відповіді

Answer 3

To solve the equation (2x-1) + (x+2)(2x-1) = 0, you can follow these steps:

1. Distribute the (x+2) term on the left side of the equation: 2x - 1 + 2x^2 - x = 0

2. Combine like terms on the left side of the equation: 2x + 2x^2 - x - 1 = 0

3. Rearrange the terms in descending order of degree (highest power of x first): 2x^2 + 2x - x - 1 = 0

4. Combine like terms again: 2x^2 + x - 1 = 0

5. Now, you have a quadratic equation in the form ax^2 + bx + c = 0, where: a = 2 b = 1 c = -1

6. To solve for x, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)

7. Plug in the values of a, b, and c into the formula: x = (-1 ± √(1^2 - 4(2)(-1))) / (2(2))

8. Simplify under the square root: x = (-1 ± √(1 + 8)) / 4 x = (-1 ± √9) / 4 x = (-1 ± 3) / 4

Now, you have two possible solutions:

1. x = (-1 + 3) / 4 = 2/4 = 1/2
2. x = (-1 - 3) / 4 = -4/4 = -1

So, the solutions to the equation (2x-1) + (x+2)(2x-1) = 0 are x = 1/2 and x = -1.