Question

( 12 · у + 18 ) · ( 1,6 - 0,2 · у ) = 0; ​

Answer 1

Ответ:   -1.5;  8.

Объяснение:

(12у+18)*(1,6-0,2у ) = 0; ​

19,2y-2.4y²+28.8-3.6y=0;

-2.4y²+15.6y+28.8=0;          [:( -2.4)]

y²-6.5y-12=0;

По т. Виета

y1+y2=6.5;

y1*y2=-12;

y1=-1.5;

y2=8.

Answer 2

To solve the equation $(12y + 18) \cdot (1.6 - 0.2y) = 0$, you can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero. So, you can set each factor equal to zero and solve for $y$.

First factor: $12y + 18 = 0$

Subtract 18 from both sides: $12y = -18$

Divide by 12: $y = \frac{-18}{12}$ $y = -\frac{3}{2}$

Second factor: $1.6 - 0.2y = 0$

Subtract 1.6 from both sides: $-0.2y = -1.6$

Divide by -0.2: $y = \frac{-1.6}{-0.2}$ $y = 8$

So, there are two solutions for $y$: $y = -\frac{3}{2}$ and $y = 8$