Question

1) -4y+10 > 2(1-y) + 24; 3) 7(6-5t) -54x-3.2)49-3(3-2z)<=1-4z​

Answer 1

Ответ:

П.с. то что на четвёртой картинке не относится к заданию

Answer 2

Let's solve each of these inequalities step by step:

1. -4y + 10 > 2(1 - y) + 24

First, distribute the 2 on the right side of the inequality:

-4y + 10 > 2 - 2y + 24

Now, combine like terms on the right side:

-4y + 10 > 26 - 2y

Next, subtract 10 from both sides of the inequality to isolate the terms containing y on the left side:

-4y > 16 - 2y

Now, add 2y to both sides to collect the y terms on the left side:

-4y + 2y > 16

Simplify:

-2y > 16

To solve for y, divide both sides by -2. Remember that when you divide by a negative number, the inequality sign flips:

y < -8

So, the solution for this inequality is y < -8.

2. 7(6 - 5t) - 54x - 3.2 < 49 - 3(3 - 2z)

First, distribute the 7 on the left side and the 3 on the right side:

42 - 35t - 54x - 3.2 < 49 - 9 + 6z

Now, combine like terms on both sides:

42 - 35t - 54x - 3.2 < 40 + 6z

Subtract 42 from both sides to isolate the terms without t, x, or z:

-35t - 54x - 3.2 < 6z - 2

Now, add 3.2 to both sides:

-35t - 54x < 6z + 0.8

Next, divide both sides by -1 (remember, when dividing by a negative number, flip the inequality sign):

35t + 54x > -6z - 0.8

Now, divide both sides by 5:

7t + 10.8x > -1.2z - 0.16

So, the solution for this inequality is 7t + 10.8x > -1.2z - 0.16.

If you have any more questions or need further clarification, feel free to ask.