Question

-3y+ 5(2y-3) 43х+2_<45​

Answer 1

[ -3y + 5(2y - 3) \leq 43x + 2 \leq 45 ]

[ 5(2y - 3) = 10y - 15 ]

[ -3y + 10y - 15 \leq 43x + 2 \leq 45 ]

[ 7y - 15 \leq 43x + 2 \leq 45 ]

[ 7y - 15 + 15 \leq 43x + 2 + 15 leq

Answer 2

It looks like you've provided an expression with variables. Let's simplify it:

$-3y + 5(2y - 3) \leq 43x + 2$

First, distribute the 5 on the left side:

$-3y + 10y - 15 \leq 43x + 2$

Combine like terms:

$7y - 15 \leq 43x + 2$

Now, add 15 to both sides to isolate the y term:

$7y \leq 43x + 17$

Finally, divide both sides by 7 to solve for y:

$y \leq \frac{43}{7}x + \frac{17}{7}$

So, the solution is $y \leq \frac{43}{7}x + \frac{17}{7}$.