Question

1/3*(12-0,6y)+0,3y=0,1y+4​

Answer 1

Ответ:

$y\in R$

Объяснение:

$\frac{1}{3}(12-0,6y)+0,3y=0,1y+4\ \ \ |\cdot3\\\\12-0,6y+0,9y=0,3y+12\\\\-0,6y+0,9y-0,3y=12-12\\\\0=0\\\\y\in R$

Answer 2

To solve the equation $\frac{1}{3}(12-0.6y) + 0.3y = 0.1y + 4$, you can follow these steps:

1. Distribute the fraction on the left side of the equation:

   $\frac{1}{3} \cdot 12 - \frac{1}{3} \cdot 0.6y + 0.3y = 0.1y + 4$

   Simplify:

   $4 - 0.2y + 0.3y = 0.1y + 4$

2. Combine like terms on both sides of the equation:

   $4 + 0.1y = 0.1y + 4$

3. Subtract 0.1y from both sides to isolate the variable terms on one side:

   $4 + 0.1y - 0.1y = 4 - 0.1y + 0.1y$

   Simplify:

   $4 = 4$

The equation simplifies to $4 = 4$, which is always true. This means that the equation has infinitely many solutions, and any value of $y$ will satisfy it. In other words, there is no unique solution to this equation, and it holds true for all real values of $y$.