Question

3(1-2у)(1+2у+4у^2)+(6у^3-1)=?

Answer 1

3(1-2у)(1+2у+4у³)+(6у³-1)=3·(1-8y³)+6y³-1=3-24y³+6y³-1=2-18y³=
=2·(1-9y³)

Answer 2

Let's simplify the expression step by step:

Given expression: $3(1-2y)(1+2y+4y^2)+(6y^3-1)$

First, let's apply the distributive property to the first part of the expression: $3(1-2y)(1+2y+4y^2) = 3(1+2y+4y^2-2y-4y^2-8y^3)$ $= 3(1-2y-8y^3)$ $= 3 - 6y - 24y^3$

Now let's simplify the second part of the expression: $6y^3 - 1$

Now we can combine the simplified expressions: $3 - 6y - 24y^3 + (6y^3 - 1)$ $= 3 - 6y - 24y^3 + 6y^3 - 1$ $= 2 - 6y - 18y^3$

So, the simplified expression is $2 - 6y - 18y^3$.