Question

(х+3)(2х-4) -------------- х-1

Answer 1

------------------------------

Answer 2

It seems like you've provided a mathematical expression that needs to be simplified. Let's go step by step:

The expression is:

$\frac{(x+3)(2x-4)}{x-1}$

We can start by factoring the numerators and the denominator:

Numerator: $(x+3)(2x-4) = 2x(x) - 4(x) + 3(2x) - 3(4)\\ = 2x^2 - 4x + 6x - 12\\ = 2x^2 + 2x - 12$

So, the numerator becomes $2x^2 + 2x - 12$.

Denominator: $x - 1$

Now we can rewrite the expression as:

$\frac{2x^2 + 2x - 12}{x - 1}$

Next, we can try to simplify the expression further by factoring the numerator if possible:

$2x^2 + 2x - 12 = 2(x^2 + x - 6)$

The quadratic $x^2 + x - 6$ can be factored as $(x + 3)(x - 2)$, so:

$2(x^2 + x - 6) = 2(x + 3)(x - 2)$

So, the simplified expression becomes:

$\frac{2(x + 3)(x - 2)}{x - 1}$

That's the simplified form of the given expression.