Question

√2х в квадрате +4√3х-2√2=0

Answer 1

Надеюсь тебе подойдет !!!!!!!

Answer 2

To solve the quadratic equation √2x^2 + 4√3x - 2√2 = 0, we can use the quadratic formula:

For any equation in the form of ax^2 + bx + c = 0, the quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In our case, a = √2, b = 4√3, and c = -2√2.

Now, let's plug these values into the quadratic formula:

x = (-(4√3) ± √((4√3)^2 - 4 * √2 * (-2√2))) / 2 * √2

x = (-4√3 ± √(48 - 4 * 2 * 2)) / 2√2

x = (-4√3 ± √(48 - 16)) / 2√2

x = (-4√3 ± √32) / 2√2

Now, let's simplify the square root of 32:

√32 = √(16 * 2) = √16 * √2 = 4√2

Substitute this back into the equation:

x = (-4√3 ± 4√2) / 2√2

Now, we can simplify the expression by canceling out the common factor of 2√2 in the numerator and denominator:

x = (-4√3 ± 4√2) / 2√2 = -2√3 ± 2

So, the solutions to the equation are:

1. x = -2√3 + 2
2. x = -2√3 - 2