
Сократи дробь 3x^2 + 7x - 6 и найдите значение при x=3 __________ x^2 - x - 12


Ответы на вопрос

Подставляем x= (3+3)*(3*3-2)= 9*7= 63
x^2-x-12= x^2+3x-4x-12=x*(x+3)-4*(x+3) = (x+3)*(x-4)
Подставляем х= (3+3)*(3-4)=9*(-1) = -9
Ответь мой ответ лучшим, пожалуйста =)



To simplify the fraction, we can factor the numerator and the denominator and then cancel out any common factors. Let's start with the numerator:
Numerator: 3x^2 + 7x - 6
To factor the numerator, we look for two numbers whose product is equal to the product of the leading coefficient (3) and the constant term (-6) and whose sum is equal to the coefficient of the middle term (7). The two numbers are 9 and -2.
So, we can write the numerator as:
Numerator: 3x^2 + 7x - 6 = 3x^2 + 9x - 2x - 6
Now, we can group the terms and factor them:
Numerator: 3x^2 + 9x - 2x - 6 = 3x(x + 3) - 2(x + 3)
Now, we can factor out the common factor (x + 3):
Numerator: 3x(x + 3) - 2(x + 3) = (3x - 2)(x + 3)
Next, let's factor the denominator:
Denominator: x^2 - x - 12
To factor the denominator, we look for two numbers whose product is equal to the product of the leading coefficient (1) and the constant term (-12) and whose sum is equal to the coefficient of the middle term (-1). The two numbers are -4 and 3.
So, we can write the denominator as:
Denominator: x^2 - x - 12 = x^2 - 4x + 3x - 12
Now, we can group the terms and factor them:
Denominator: x^2 - 4x + 3x - 12 = x(x - 4) + 3(x - 4)
Now, we can factor out the common factor (x - 4):
Denominator: x(x - 4) + 3(x - 4) = (x + 3)(x - 4)
Now, the fraction becomes:
(3x^2 + 7x - 6) / (x^2 - x - 12) = (3x - 2)(x + 3) / (x + 3)(x - 4)
Notice that (x + 3) appears in both the numerator and denominator, so we can cancel them out:
(3x^2 + 7x - 6) / (x^2 - x - 12) = (3x - 2) / (x - 4)
Now, to find the value when x = 3, we substitute x = 3 into the simplified expression:
(3x - 2) / (x - 4) = (3 * 3 - 2) / (3 - 4) = (9 - 2) / (-1) = 7 / -1 = -7
So, when x = 3, the value of the expression is -7.


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