Question

X2-25=0 решить уровненные

Answer 1

$x^2-25=0\\\\(x-5)(x+5)=0\\\\x-5=0\; \; \; ili\; \; \; x+5=0\\\\\underline {x_1=5\; \; \; ili\; \; \; x_2=-5}$

Answer 2

To solve the equation $X^2 - 25 = 0$, we can use the method of factoring the quadratic equation. The equation can be rewritten as:

$X^2 - 25 = 0$

Now, notice that this is a difference of squares since $25 = 5^2$. So we can factor the equation as follows:

$(X + 5)(X - 5) = 0$

Now, using the zero-product property, we know that the equation is equal to zero only if either $X + 5 = 0$ or $X - 5 = 0$. Let's solve for $X$ in both cases:

1. $X + 5 = 0$ Subtract 5 from both sides: $X = -5$

2. $X - 5 = 0$ Add 5 to both sides: $X = 5$

So the solutions to the equation $X^2 - 25 = 0$ are $X = -5$ and $X = 5$.