Question

3mn-m/4m+n * 16m^2-n^2/3n-1

Answer 1

$\frac{3mn-m}{4m+n} * \frac{16 m^{2}- n^{2} }{3n-1}= \frac{m(3n-1)}{4m+n} * \frac{(4m+n)(4m-n)}{3n-1} =m(4m-n)=$ $4 m^{2}-mn$

Answer 2

To simplify the given expression, follow these steps:

Step 1: Factor the expressions. Step 2: Cancel out common factors. Step 3: Perform any remaining simplifications.

Given expression: (3mn - m) / (4m + n) * (16m^2 - n^2) / (3n - 1)

Step 1: Factor the expressions. 16m^2 - n^2 can be factored as (4m + n)(4m - n).

Step 2: Cancel out common factors. Now, look for common factors in the numerator and denominator to simplify the expression.

Numerator: 3mn - m = m(3n - 1)

Denominator: 4m + n and 4m - n cannot be canceled out as they are part of separate terms.

Step 3: Perform remaining simplifications. The expression now becomes:

m(3n - 1) / (4m + n) * (4m + n)(4m - n) / (3n - 1)

The (4m + n) term in the numerator cancels out with the (4m + n) term in the denominator, leaving us with:

m(4m - n) / (3n - 1)

So, the simplified expression is: m(4m - n) / (3n - 1)