Question

запишите произведение в виде степени а) (х/2) (х/2) (х/2) (х/2); б)(-3mn) (-3mn) (-3mn); в)(x-y) (x-y) (x-y) (x-y) (x-y); г)m*m^3*m^2*m^5; е)(b^3)^5*(b^2)^4*b;​

Answer 1

Ответ:

Объяснение:

a)(х/2) (х/2) (х/2) (х/2)=(x/2)^4

б)(-3mn) (-3mn) (-3mn)=(-3mn)³

в)(x-y) (x-y) (x-y) (x-y) (x-y)=(x-y)^5

г)m*m³*m²*m^5=m^(1+3+2+5)=m^11

е)(b³)^5*(b²)^4*b=b^15*b^8*b=b^(15+8+1)=b^24

Answer 2

а) (х/2) (х/2) (х/2) (х/2) = (х/2)^4 = х^4/16 б) (-3mn) (-3mn) (-3mn) = (-3mn)^3 = -27m^3n^3 в) (x-y) (x-y) (x-y) (x-y) (x-y) = (x-y)^5 = x^5 - 5x^4y + 10x^3y^2 - 10x^2y^3 + 5xy^4 - y^5 г) mm^3m^2m^5 = m^(1+3+2+5) = m^11 е) (b^3)^5(b^2)^4b = b^(35) * b^(2*4) * b = b^15 * b^8 * b = b^(15+8+1) = b^24