Question

B^2-8ab разделить дробью на b^2-64a^2; при a=корень из 2,b=корень из 8.

Answer 1

$\frac{ b^{2}-8ab }{ b^{2}-64 a^{2} } = \frac{b(b-8a)}{(b-8a)(b+8a)}= \frac{b}{b+8a}\\\\ \frac{ \sqrt{8} }{ \sqrt{8}+8 \sqrt{2} } = \frac{2 \sqrt{2} }{2 \sqrt{2}+8 \sqrt{2} } = \frac{2 \sqrt{2}}{10 \sqrt{2} } =0,2$

Answer 2

To evaluate the expression (B^2 - 8ab) divided by (b^2 - 64a^2) when a = √2 and b = √8, we can substitute these values into the expression and perform the calculations step by step.

Given: a = √2 b = √8

Expression to evaluate: (B^2 - 8ab) / (b^2 - 64a^2)

Now, substitute the given values: B^2 = (√8)^2 = 8 ab = (√2)(√8) = √16 = 4 b^2 = (√8)^2 = 8 a^2 = (√2)^2 = 2

Now, the expression becomes: (8 - 8 * 4) / (8 - 64 * 2)

Perform the calculations: (8 - 32) / (8 - 128) = -24 / (-120) = 1/5

So, when a = √2 and b = √8, the expression (B^2 - 8ab) divided by (b^2 - 64a^2) equals 1/5.