Question

Сократите дробь: 27a^2-36ab+12b^2/9a^2-4b^2 7a^2(ab^2-9a)/3a(21a-7ab)

Answer 1

Ответы на фото обведены.
Очепятка там 2b

Answer 2

Вот решение(все2))))) У меня там небольшая ошибочка была , но я исправила

Answer 3

To simplify the fractions, we need to factorize the numerators and denominators and then cancel out common factors. Let's start with each fraction:

1. (27a^2 - 36ab + 12b^2) / (9a^2 - 4b^2) Factor numerator: 27a^2 - 36ab + 12b^2 = 3(9a^2 - 12ab + 4b^2) = 3(3a - 2b)^2 Factor denominator: 9a^2 - 4b^2 = (3a + 2b)(3a - 2b) The fraction becomes: 3(3a - 2b)^2 / (3a + 2b)(3a - 2b) Now, we can cancel out the common factor (3a - 2b) from both the numerator and denominator: Result: 3 / (3a + 2b)

2. (7a^2(ab^2 - 9a)) / (3a(21a - 7ab)) Factor numerator: 7a^2(ab^2 - 9a) = 7a^2 * a(b^2 - 9) = 7a^3(b^2 - 9) Factor denominator: 3a(21a - 7ab) = 3a * 7a(3 - b) = 21a^2(3 - b) The fraction becomes: 7a^3(b^2 - 9) / 21a^2(3 - b) Now, we can cancel out the common factor (7a^2) from both the numerator and denominator: Result: (b^2 - 9) / (3 - b)

So, the simplified fractions are:

1. 3 / (3a + 2b)
2. (b^2 - 9) / (3 - b)