Question

3cos180°+5ctg270°-2tg0°+3tg180°-tg60°=

Answer 1

 3cos180° + 5ctg 270° - 2tg0 - sin 60° = 3*(-1) + 5*0 - 2*0 - √3/2 = -3 + 0 + 0  -√3/2=-3-√3/2

Answer 2

To solve this trigonometric expression, let's evaluate each term one by one:

1. $3 \cos(180°)$: The cosine of 180 degrees is -1. $3 \times (-1) = -3$.

2. $5 \cot(270°)$: The cotangent of 270 degrees is 0. Note that cotangent is undefined at multiples of 90 degrees. However, by convention, we treat $\cot(270°)$ as 0. $5 \times 0 = 0$.

3. $-2 \tan(0°)$: The tangent of 0 degrees is 0. $-2 \times 0 = 0$.

4. $3 \tan(180°)$: The tangent of 180 degrees is 0. $3 \times 0 = 0$.

5. $-\tan(60°)$: The tangent of 60 degrees is $\sqrt{3}$. $-\sqrt{3}$.

Now, add up all the results: $-3 + 0 + 0 + 0 - \sqrt{3} = -3 - \sqrt{3}$.

So, the final result is $-3 - \sqrt{3}$.