Question

4*(2-3y)-(6-y)-2*(3y+4)=-17y-6 тождество

Answer 1

8-12у-6+у-6у-8=-17у-6
-6-17у=-17у-6
-17у-6=-17у-6

Answer 2

To verify whether the given equation is an identity, we need to check if it holds true for all values of 'y'. Let's simplify both sides of the equation and see if they are equal:

Left-hand side (LHS): 4*(2-3y) - (6-y) - 2*(3y+4)

Step 1: Distribute the multiplication. LHS = 8 - 12y - (6 - y) - 6y - 8

Step 2: Simplify the expression inside the parentheses. LHS = 8 - 12y - 6 + y - 6y - 8

Step 3: Combine like terms. LHS = -12y - 6y + y + 8 - 6 - 8

LHS = -17y - 6

Now, let's compare this with the right-hand side (RHS):

Right-hand side (RHS): -17y - 6

As you can see, the LHS simplifies to -17y - 6, which is exactly the same as the RHS. Since the LHS and RHS are equal for all values of 'y', the given equation is indeed an identity.