Question

1-4sin2a×cos2d/(sina+cosa)2-2cosa×sin(-a)=1

Answer 1

Решение смотрите на фотографии..

Answer 2

Let's simplify the given expression step by step:

1. Recall the trigonometric identity: sin^2(a) + cos^2(a) = 1

2. Rewrite sin^2(a) as 1 - cos^2(a): 1 - cos^2(a) = sin^2(a)

3. Rewrite cos^2(a) as 1 - sin^2(a): 1 - sin^2(a) = cos^2(a)

Now, let's simplify the expression:

1 - 4sin^2(a) × cos^2(d) / (sin(a) + cos(a))^2 - 2cos(a) × sin(-a) = 1

Using the trigonometric identities above, we get:

1 - 4(1 - cos^2(a)) × cos^2(d) / (sin(a) + cos(a))^2 - 2cos(a) × (-sin(a)) = 1

Simplify further:

1 - 4cos^2(d) + 4cos^2(a) × cos^2(d) / (sin(a) + cos(a))^2 + 2cos(a) × sin(a) = 1

Since we still have terms involving both a and d, we cannot further simplify the equation without more information or specific values for a and d. If you have any specific values for these variables, please provide them, and I can help you further simplify the equation or solve for the unknowns.